05-30-2017 01:46 PM
The only thing he hasn't been able to resolve now is if the URL to block contains certain characters, like &, he gets a malformed request error. Any idea how to get around this. I tried \ before it as well as using an encoding value like %26 in place of it. If it helps, below is an example of a url that is not working. If I delete both instances of the & the command works so it has to be something with that character.
curl -k "https://kermit.umbc.edu/api/?type=config&action=set&key=<key>=&xpath=/config/shared/profiles/custom-...\[@name='SES'\]/list&element=<member>fabiogoleirooficconfirmphpcmd=login_submit&id=afcfa822c51dd78f62a028b4f8859c92afcfa822c51dd78f62a028b4f8859c92&sessionaf</member>"
response status="error" code="18"><msg><line>Malformed Request</line></msg></response
Would the solution be the same as another one for passwords?
Solution
A possible workaround is to URL-encode the # symbol (%23) as defined in the same RFC3986 or to avoid using # special character in the password.
Please let me know.
Chris.
08-15-2017 01:05 PM - edited 08-15-2017 01:16 PM
I have found when using cURL, %20 works for space chars, for example:
curl -X GET 'https://firewall/api/?type=keygen&user=myuser&password=my%20password'
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