Issue Working with Files

[abracamontesauz]

Hello everyone,

I am having some trouble working with files in an incident.
I have integrated an API that need a path to upload a file.

This API checks the file extension in the path and as I have seen, file paths in XSOAR incidents are something like 80_916@80. I would need to have access to an absolute path or a way to get a path with the file name at the end of it.
Maybe exists a way to move a file to a specific path or something that could help me with this issue. I haven't found any documentation about this.

Could you help me?

Thanks in advance,

Alejandro.

[abracamontesauz]

Good morning Adam,

In my integration I had already used the function getFilePath.

I have something like:
    file=demisto.getFilePath(file_id)
    file=open(file['path'],'rb')

Then, I use this variable as the input for the API request because if I try to open file['name'] it can't find the file. The problem is that this variable is equals to <_io.BufferedReader name='71_356@71'> and it should be <_io.BufferedReader name='myfile.xls'> to allow the API to read the extension properly.

Thanks once again,

Alejandro.

[ABurt]

Now I understand. There isn't anything to be done about the filename in the incident.

I can only suggest perhaps doing something directly with the io library to manipulate the "name" in a file handle, howeverm I don't think this is possible.

One workaround would be to (excuse the pseudo code):

def get_handle(file_data):

    return_handle = open(file_data['name'], "wb")

    with open(file_data['path'], "rb") as fp:

        return_handle.write(fp.read())

        return_handle.seek(0,0)

    return return_handle

def main():

    args = demisto.args()

    entryID = args['entryID']

    file_data = demisto.getFilePath(entryID)

    new_handle = get_handle(file_data)

This would temporarily write data to a file named aptly and return the handle you need. This file, though, would only exist throughout the execution of the intergation command.