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03-13-2013 01:34 PM
I have URL filtering configured that blocks pornography, but if I search in Google for pornography and then click on images, pornographic images are accessible. I know that I can block these in Chrome browser, but how do I block them as a policy via the firewall?
03-13-2013 03:25 PM
Thank you, will safesearch 4.1 work with PAN-OS 5.0?
03-14-2013 06:17 AM
Yes it works with 5.0
03-14-2013 01:48 PM
It appears that the safesearch files are working, but... when I go to Google and type a search for something explicit, it does the search via https: and goes through, if I search again by stripping the S off of https: the policy is in affect. If I lock safesearch in chrome the policy still works. The policy also disables the ability to unlock safesearch, but I can bypass that by closing the browser, cleaning out cashed pages and starting all over again, I can again reach explicit images bypassing my URL filter. What am I doing wrong and what else can I do, so that this control is effective. First step is google, next will be Bing and Yahoo, but I first want to understand what I'm doing wrong with Google.
03-16-2013 02:32 PM
Ya, I looking at the same thing, what I notice is if you set your PA as a Cert authority on your network you can set it to decrypt the search traffic only. This should allow you to block that traffic in theory. I have not had a chance to test it out yet. As for Bing I have been looking into that myself and noticed a couple of things. You don’t have to worry about the https with Bing it doesn’t really search that way. As for the filter:
adlt=off is when safesearch is set to off
adlt=moderate is when moderate search is turned on
adlt=strict is for Strict searching
I have not had time to create and application for it to test yet.
04-24-2015 09:34 AM
JeffC, true, google search uses SSL, so you would need also to configure Decryption Policy. Page 361 of PAN-OS 6.1 Admin Guide, has basic information on it.
04-27-2015 06:32 AM
Without ssl decryption the PaloAlto won't be able to see what is traversing in https.
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